Ruby – Find Block Iterates Evaluation – step Method with Examples

# import date library
    require 'date'
# on 2012,1,1 the day was Sunday
    x = Date.new(2012).step(Date.new(2012,1,1)).select{|d| d.monday?}.size 
# on 2012,1,2 first monday of that year
    x = Date.new(2012).step(Date.new(2012,1,2)).select{|d| d.monday?}.size
    puts x

Output:
0
1

NOTE: From the above example, it is easy to understand that .step method iterates until it find the required day which is also indicated in the code. This code tells that, this is the first monday of that particular year.

Date.new(x).step

x – where x is any valid date object. This parameter is required.

If the x parameter is not a valid date object the step method will return an error and it could be due to the wrong format of the date in a code, the use of zero or the missing of any other character.

The step method will return the number of the special day indicated in the code from the whole year like this is the 2nd, 10th or 15th monday of that year.

# import date library
    require 'date'
    x = Date.new(2012).step(Date.new(2012,1,23)).select{|d| d.monday?}.size
    puts x

Output:
4

# import date library
   require 'date'
   x = Date.new(2012).step(Date.new(2012,2,20)).select{|d| d.monday?}.size
   puts x

Output:
8

# import date library
    require 'date'
    # you can get desired year 
    x = Date.new(2012).step(Date.new(2012,3,12)).select{|d| d.monday?}.size
    x = Date.new(2012).step(Date.new(2012,4,16)).select{|d| d.monday?}.size
    puts x

Output:
11
16