Log1p() function is used to find the natural logarithm of 1 plus its argument x. It is more accurate than Log(1 + x) when x is near zero. The standard math package of Go programming language has Log1p() function.
Syntax of Log1p() Function in Go Language
The syntax of Log1p() function in Go Language is:
1 | func Log1p(x float64) float64 |
Note: float64 is a data type in Go language which has IEEE-754 64-bit floating-point numbers.
Special cases are:
Log1p(+Inf) = +Inf
Log1p(±0) = ±0
Log1p(-1) = -Inf
Log1p(x < -1) = NaN
Log1p(NaN) = NaN
Parameters of Log1p() Function in Go Language
x – Where x is any Valid float64 Input value. This parameter is required.
Error Handling
If the
If there is no argument (
x parameter is not a number (numeric value) Log1p() function returns an error .If there is no argument (
x – input value) passes to the function, then the compiler will produce an error.
Return Value of Log1p() Function in Go Language
Log1p() function will return the natural logarithm of 1 plus its parameter x. It is more accurate than Log(1 + x) when x is near zero.
Go Log1p() Function Example 1
1 2 3 4 5 6 7 8 9 10 | package main import "fmt" import "math" func main() { var x float64 x = math.Log1p(-7.63) fmt.Println(x) } |
Output:
NaN
GoLang Log1p() Function Example 2
1 2 3 4 5 6 7 8 9 10 | package main import "fmt" import "math" func main() { var x float64 x = math.Log1p(4.33) fmt.Println(x) } |
Output:
1.6733512381777533
GoLang Log1p() Function Example 3
1 2 3 4 5 6 7 8 9 10 | package main import "fmt" import "math func main() { var x float64 x = math.Log1p(2) fmt.Println(x) } |
Output:
1.0986122886681096
